The number of litres of O2 at 298 K as well as 1.00 bar are generated in 1.50 human resources in an electrolytic cell operating at a currpilsadiet.comt of 0.0200 A?Answer: 0.0069 L Description:2 WATER(l )-- >

O2(g)+4H+(aq

) + 4e-

no of moles= it/eF

NO of moles of O2 created = (Currpilsadiet.comt in Ampere x Time in 2nd)/ (Faraday consistent x Variety of electrons needed)

Moles of O2 generated = (0.02 x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798 x 10 ^ -4 moles

Utilizing perfect gas formula,

P V = n R T

Where, P is the stress,

V is the quantity,

n is the variety of moles,

R is the gas constant, and also T is the temperature level

We have, 1 bar = 0.986923 atm machine

Replacing the worths,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm machine mol K x 298 K)/ 0.986923 atm machine = 0.0069 L

Quantity of O2 generated = 0.0069 L


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